Saša said:MusicMan said:Extremely interesting.
I can only add that if the companion is a 'dark star', then it will be a neutron star, and electrically neutral, as opposed to Sol which is emitting a stream of protons, so it must be positively charged.
Not sure how this will affect your calculation, my guess is that it would not.
Maybe it is the companion that is grounding Sol.
To my knowledge of astronomy, neutron star would be too massive to be Solar companion. I think the companion was designated to be brown dwarf (Wiki:Brown dwarf), which is defined (for most astronomers) as an object with mass [15 MJupiter , 75 MJupiter].
When taken that companion mass is approx. 3.4% of MSun, the obtained value for Mcompanion is 36.6 MJupiter [1] which lies nicely in the above interval.
And brown dwarfs would have all the properties (including electromagnetic activity) of a very large planet (like big Jupiter) and/or not quite yet ignited star (according to SSM - Standard Solar Model).
[1] https://en.wikipedia.org/wiki/Jupiter_mass
Thanks for the correction Sasa, I assumed they were one and the same thing.
D'uh! I should have stayed at school longer..