David George
The Force is Strong With This One
I was going to leave this for tomorrow, but I started writing and it went fairly quickly, so I will post this now.
Richard Feynman gives a version of the two-slit experiment using photons in "QED", p. 80-81, as follows. Photons/light waves are sent to a photomultiplier detector through a barrier in which are two holes. With one hole closed and the other open, the detector clicks are approximately equal for each hole: approximately 1% of the time, the detector clicks. Paraphrasing, 1 out of 100 photons is detected for each hole, with the other hole closed.
"When we open both holes, we get a complicated answer, because interference is present: If the holes are a certain distance apart, we get more clicks than the expected 2% (the maximum is about 4%); if the two holes are a slightly different distance apart, we get no clicks at all.
"One would normally think that opening a second hole would always increase the amount of light reaching the detector (D), but that's not what actually happens...."
With detectors A and B placed on both holes with varied spacing, "...the detectors at A and B never go off together - either A or B goes off. The photon does not divide in two; it goes one way or the other.
"Furthermore, under such conditions the detector at D goes off 2% of the time - the simple sum of the probabilities for A and B (1% + 1%). The 2% is not affected by the spacing between A and B; the interference disappears when detectors are put in at A and B!"
This passage illustrates what Feynman called the "central mystery" of modern physics, the seeming dual quality of light: that of a wave with the property of wave interference, and of a particle or wave packet, a photon. The light takes the form of a wave when it is not being observed (detected), but of a photon when it is being observed. Feynman uses the term photon throughout, but in classical physics it was shown by Fresnel (or Young, I don't remember which) in the 19th Century that a wave can act as a particle, i.e. it can "impact" at a specific point. In other words, a photomultiplier tube can detect a wave as a particle. So without the detail of the experiment, photon interference can be treated as wave interference. The mystery, then, is in why the photon/wave interferes when no detectors are present, but does not interfere when A and B are present. The answer lies in the assumption that "the photon does not divide in two; it goes one way or the other", and what that implies.
I question this assumption as follows. Imagine our two eyes are the two holes used in experiment. Viewing a scene - for example, a darkened room in which there is only a dim candle - we close each of our eyes in turn. We see a slightly different version of the scene through each eye. But we see the candle through both eyes. It is not reasonable that with one eye closed, we would deny that the candle we see with the open eye is not also available to the closed eye, if it were open. If we treat the candle light as a photon, we can say that if there is a photon at the open eye, there is also a photon at the closed eye. And if both our eyes are open, the photon interferes: this is seen in the experiment. So we understand the case when one or the other hole is open, and when both holes are open.
Now consider the case when there are detectors A and B at the two holes. What happens? A photon is detected 2 out of 100 times at A or B, and also a photon is detected 2 out of 100 times at D. But are these the same photons? I would say, no, a photon detected at A or B is not the same photon detected at D. They are different photons. I say this because it is not likely that a single photon would be detected at A or B, and also at D. The photon detected at A or B is absorbed (its momentum-energy is transferred), because it activates the photomultiplier. It cannot both transfer its energy to the photomultiplier and continue on to activate the detector at D. So there are four different photons detected: two at A and B, and two at D.
Does this mean that, out of 100 photons sent, two are detected by A and B, while two are undetected by A and B? How would two photons pass through A and B undetected and without interfering? Here, judging by the evidence of our eyes and the candle, we remember that if there is a photon at A, there must also be a photon at B. Would the photon at one hole pass through undetected, while the photon at the other hole does not pass through but is not detected either? That would have to be the case in order for a single photon to be detected. And if both photons pass through undetected, still they must interfere.
The only reasonable scenario, then, is that one photon is detected at A or B, while the other photon passes through the detectors at A and B and is detected as a single photon at D. There is no interference, and the statistics are accounted for. And since a photon can be treated as a wave, it is a wave that is detected at A, B and D. There is no photon in physical reality.
The question then becomes, why is the photon/wave detected at A (for example) but not at B? This is due to the form of the wave, which is an electromagnetic wave - a wave with two components, a magnetic component and an electric component, orthogonal to each other. The shape, or structure, of this wave, may not be well understood. A wave is a collective motion, but the electromagnetic field is a vacuum - so, as the physicists ask, what is waving? The electromagnetic wave is modelled on a pressure wave - that is, a wave consisting of slight changes in pressure, which moves in waves. However, the electromagnetic wave is also modelled as a plane wave, spreading orthogonal to the wave front, whereas a pressure wave is like a series of pulses over a wide area wave front (I think!). I believe it is more realistic to trreat the electromagnetic wave as a pressure wave with two components - that is, two separate pressure fronts. And these two components are not identical in different locations. Just as we see a slightly different scene through each of our eyes, any spatially distant locations will sense a slightly different pressure wave. The wave form at detector A is not, and cannot be, the same as the wave form at detector B. The question then is, what is the pressurized medium that can transmit pressure waves? That "mystery" replaces the wave-particle mystery, and must be explained, which I will do in a future post.
Now I am taking a break. In the next post I will describe the two-slit experiment with electrons.
Richard Feynman gives a version of the two-slit experiment using photons in "QED", p. 80-81, as follows. Photons/light waves are sent to a photomultiplier detector through a barrier in which are two holes. With one hole closed and the other open, the detector clicks are approximately equal for each hole: approximately 1% of the time, the detector clicks. Paraphrasing, 1 out of 100 photons is detected for each hole, with the other hole closed.
"When we open both holes, we get a complicated answer, because interference is present: If the holes are a certain distance apart, we get more clicks than the expected 2% (the maximum is about 4%); if the two holes are a slightly different distance apart, we get no clicks at all.
"One would normally think that opening a second hole would always increase the amount of light reaching the detector (D), but that's not what actually happens...."
With detectors A and B placed on both holes with varied spacing, "...the detectors at A and B never go off together - either A or B goes off. The photon does not divide in two; it goes one way or the other.
"Furthermore, under such conditions the detector at D goes off 2% of the time - the simple sum of the probabilities for A and B (1% + 1%). The 2% is not affected by the spacing between A and B; the interference disappears when detectors are put in at A and B!"
This passage illustrates what Feynman called the "central mystery" of modern physics, the seeming dual quality of light: that of a wave with the property of wave interference, and of a particle or wave packet, a photon. The light takes the form of a wave when it is not being observed (detected), but of a photon when it is being observed. Feynman uses the term photon throughout, but in classical physics it was shown by Fresnel (or Young, I don't remember which) in the 19th Century that a wave can act as a particle, i.e. it can "impact" at a specific point. In other words, a photomultiplier tube can detect a wave as a particle. So without the detail of the experiment, photon interference can be treated as wave interference. The mystery, then, is in why the photon/wave interferes when no detectors are present, but does not interfere when A and B are present. The answer lies in the assumption that "the photon does not divide in two; it goes one way or the other", and what that implies.
I question this assumption as follows. Imagine our two eyes are the two holes used in experiment. Viewing a scene - for example, a darkened room in which there is only a dim candle - we close each of our eyes in turn. We see a slightly different version of the scene through each eye. But we see the candle through both eyes. It is not reasonable that with one eye closed, we would deny that the candle we see with the open eye is not also available to the closed eye, if it were open. If we treat the candle light as a photon, we can say that if there is a photon at the open eye, there is also a photon at the closed eye. And if both our eyes are open, the photon interferes: this is seen in the experiment. So we understand the case when one or the other hole is open, and when both holes are open.
Now consider the case when there are detectors A and B at the two holes. What happens? A photon is detected 2 out of 100 times at A or B, and also a photon is detected 2 out of 100 times at D. But are these the same photons? I would say, no, a photon detected at A or B is not the same photon detected at D. They are different photons. I say this because it is not likely that a single photon would be detected at A or B, and also at D. The photon detected at A or B is absorbed (its momentum-energy is transferred), because it activates the photomultiplier. It cannot both transfer its energy to the photomultiplier and continue on to activate the detector at D. So there are four different photons detected: two at A and B, and two at D.
Does this mean that, out of 100 photons sent, two are detected by A and B, while two are undetected by A and B? How would two photons pass through A and B undetected and without interfering? Here, judging by the evidence of our eyes and the candle, we remember that if there is a photon at A, there must also be a photon at B. Would the photon at one hole pass through undetected, while the photon at the other hole does not pass through but is not detected either? That would have to be the case in order for a single photon to be detected. And if both photons pass through undetected, still they must interfere.
The only reasonable scenario, then, is that one photon is detected at A or B, while the other photon passes through the detectors at A and B and is detected as a single photon at D. There is no interference, and the statistics are accounted for. And since a photon can be treated as a wave, it is a wave that is detected at A, B and D. There is no photon in physical reality.
The question then becomes, why is the photon/wave detected at A (for example) but not at B? This is due to the form of the wave, which is an electromagnetic wave - a wave with two components, a magnetic component and an electric component, orthogonal to each other. The shape, or structure, of this wave, may not be well understood. A wave is a collective motion, but the electromagnetic field is a vacuum - so, as the physicists ask, what is waving? The electromagnetic wave is modelled on a pressure wave - that is, a wave consisting of slight changes in pressure, which moves in waves. However, the electromagnetic wave is also modelled as a plane wave, spreading orthogonal to the wave front, whereas a pressure wave is like a series of pulses over a wide area wave front (I think!). I believe it is more realistic to trreat the electromagnetic wave as a pressure wave with two components - that is, two separate pressure fronts. And these two components are not identical in different locations. Just as we see a slightly different scene through each of our eyes, any spatially distant locations will sense a slightly different pressure wave. The wave form at detector A is not, and cannot be, the same as the wave form at detector B. The question then is, what is the pressurized medium that can transmit pressure waves? That "mystery" replaces the wave-particle mystery, and must be explained, which I will do in a future post.
Now I am taking a break. In the next post I will describe the two-slit experiment with electrons.