combsbt
Jedi Master
David George said:We find, first, that the ratio of rotational frequency to "force" or "potential" is equivalent to the ratio of q to h. So we can assign a potential/force and a frequency to each rotating sphere as follows (with electron (e) or proton (p) in brackets):
f (e) / v (e) = f (p) / v (p) = q / h
In order to find a frequency, and hence a potential/force, we can refer to the known quantities by converting between the Einstein and Planck equations, E = mc^2 = h * f. We find values for the proton and electron as follows:
f (e) = 1.235 589 912 e20 rotations per second
f (p) = 2.268 731 717 e23 rotations per second
v (e) = 510 998.8962 volts
v (p) = 938 271 988.2 volts
These values of v (e) and v (p) are identical to the mass-energy values of the conventional treatment, but here the units are not "electronvolts/c^2" but simply volts. What this property actually is may not be identifiable in terms of volts, but it represents the same phenomenon represented by the Josephson constant K: in other words, a "voltage" of the electron or proton, combined with the elementary charge q, represents the same energy as a "frequency" of each body combined with Planck's constant h. They are two faces of the same phenomenon in the same way that, according to the Josephson constant, voltage produces frequency and vice versa. The significance of this relation of voltage to frequency may appear when we find (using the values above) that:
v (e) * v (p) = 4.794 559 503 e14
K (2 q / h) = 4.835 978 791 e14
There is a "factor" difference here of 1.00863881. As we proceed we will find, if not a complete explanation, a calculation that eliminates this difference. For the time being it must be remembered that the values provided by current information on the mass of the proton and electron are found by measuring free particles, not system particles. But here we are dealing with the bodies in their system state.
I randomly stumbled across this thread again and decided to revisit this confusion about units. I don't know where I messed up before in getting Volts/Second because David George was right in that it turns out to just be Volts.
Here is why: Basically all he has done taken the Energy of an electron and divided it by the Charge of an electron, resulting in this unit of Volts. This is because Volts are defined as units of Energy/Charge, so (Energy/Charge)=(Energy/Charge), no problem here.
The reason the number works out to be the same as the mass of an electron given in eV/c^2 units is because the definition of the electron volt is based off of the charge of an electron and a potential difference of one volt.
wikipedia said:By definition, it is the amount of energy gained (or lost) by the charge of a single electron moved across an electric potential difference of one volt. Thus it is 1 volt (1 joule per coulomb, 1 J/C) multiplied by the negative of the electron charge (−e, or −1.602176565(35)×10−19 C).
I don't know why it seemed so confusing before.