Numerology and The Wave?

[rymw]

I just started re-reading The Wave book 1 and something about the wave's last arrival mentioned by the C's caught my attention. It had been 309,882 year since it last arrived in 1994.

So I added 21 years to it now that it's 2015 and the figure became
309,903.

Does anyone see any signifinance in this figure of 3's 0's and 9's? It's like a palindrome and when whole or split by the comma - 309 and 903 - all are divisible by the prime number 3....

 

[Altair]

I just started re-reading The Wave book 1 and something about the wave's last arrival mentioned by the C's caught my attention. It had been 309,882 year since it last arrived in 1994.

So I added 21 years to it now that it's 2015 and the figure became
309,903.

Does anyone see any signifinance in this figure of 3's 0's and 9's? It's like a palindrome and when whole or split by the comma - 309 and 903 - all are divisible by the prime number 3....

The number 309,903 looks pretty symmetrical. It could be a symbol of (accomplishing) balance.

 

[Mal7]

Interesting.

If you add the digits of any number up, and the resulting number is divisible by 3, then the original number will also be divisible by 3.

E.g. 2451.
2+4+5+1=12
12 is divisible by 3, so 2451 must be also.

Or you can go one or more steps further:
2+4+5+1 = 12
1+2 = 3
3 is divisible by 3, so 2451 must be also.

There is a mathematical proof for why this works, which I can't remember.

But it follows that any number made up only of the digits 3, 9, and 0 will be divisible by 3.

e.g. 39, 903, 990, 333309, 99903, 9990003339990 will all be divisible by 3.

 

[Martfotai]

Interesting.

If you add the digits of any number up, and the resulting number is divisible by 3, then the original number will also be divisible by 3.

E.g. 2451.
2+4+5+1=12
12 is divisible by 3, so 2451 must be also.

Or you can go one or more steps further:
2+4+5+1 = 12
1+2 = 3
3 is divisible by 3, so 2451 must be also.

There is a mathematical proof for why this works, which I can't remember.

But it follows that any number made up only of the digits 3, 9, and 0 will be divisible by 3.

e.g. 39, 903, 990, 333309, 99903, 9990003339990 will all be divisible by 3.

When you add the total sum of each integer in the given number, you are essentially finding the mod9 equivalence (modular arithmetic uses 'clock face' counting instead of a number line; i.e. think of a 12 hour analogue clock face where 13-o'clock is 'congruent' or equal to 1-o'clock. If you have a clock with only 9 hours, 10 = 1, 11=2, 12=3, etc.). Because of this, any number, when reduced to a single digital root in mod9 which is a 0, 3, 6 or 9 will also be divisible by 3. If you are looking at it in terms of mod3, 10 = 1, as it does in mod9.

 

[MusicMan]

Palindromic numbers happen all the time.
Next one you may be interested in is 310,013.
Perhaps we should stop there.