Seminars at Quantum Future School, still have those?
- Thread starter Cyre2067
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highmystica
Jedi Master
er ... were they asking the same price as they were before lunch or after lunch did they choose to ask the same price as the other sisters ... I'm beginning to suspect this answer might be imposible, but I could be wrong ...
without understanding what you meant in the original post I certainly can say there is now way to answer it for me - without assumptions that is ... and even then I'm not sure if I could figure it out -
without understanding what you meant in the original post I certainly can say there is now way to answer it for me - without assumptions that is ... and even then I'm not sure if I could figure it out -
In fact, c+d=10 etc. So you get eight equation for six unknows. Humanly impossible to solve. But super-humans (and we have such among our Forum members) can do it. Today is the last day to think about it. Tomorrow, perhaps, John G, and whoever else will solve it, will tell us their method....Saman said:
highmystica
Jedi Master
hey - the logitician in me still says this is unaswerable without understanding more fully what you said in the originial question ... the mystic in me say 3.51 ... now the .01 thing I can't even explain ... without understanding what your originally said this is worse than dealing with the uncertainity principle, because it requires me to assume what you said ... help.
It is necessary to master Space and Time. Let's start with space. Remember, in 4th density there is no 'left" and no "right", but before solving the problems emerging in 4D, let's first look at a problem in 1D. Here is the problem:
Note: As in real life, not all in the above is 100% clear. For instance, it is not clear whether "first to the left" refers to "looking from the street" or "looking from inside the bungalow" - that kind of uncertainty is a daily bread in 4D, so take into account both possibilities and find the solution for each interpretation.
Remember, the fish without bones is a common image in alchemy and one that Jung refers to in Aion, which is his book on the nature of the Self. So: Who got the fish?
Note: As in real life, not all in the above is 100% clear. For instance, it is not clear whether "first to the left" refers to "looking from the street" or "looking from inside the bungalow" - that kind of uncertainty is a daily bread in 4D, so take into account both possibilities and find the solution for each interpretation.
highmystica
Jedi Master
I have a similar problem to what I had before ...
the phrase
"The green bungalow is next to the left of the white bungalow" is where I'm having a bit of trouble ... is it the first house on the left, or the house one step beyond that (on the left side)?
The vagueness in what you say *seems* to point to a desired vagueness in response ... now I have read a bit of alchemy, but never noticed the fish without bones thing, sorry only had the least bit of jung and have no clue about aion. So hey, how about the AMERICAN, who has fish and cat's, smokes pall mall, yet prefers dunhill ... my pad is white, but I would like blue ... and I drink both beer and coffee, or then I can bring up the pisces aquarian cusp thing (birds and fish) ... but to be needlessly cryptic is just that ... it all comes down to understanding what is said ... without understanding that phrase I quoted above from the puzzle I cannot figure it out ... even if I solved it it would be for the wrong reasons ... I know english is not your native tongue, so the problem in and of itself is unclear but I wonder if you intended it to be as unclear as I am making it ...
I suspect that your more recent logic puzzle was like the last one and I thank you for making it less math entisive, but I cannot solve it without making assumptions and so by my standards it is flawed (not the puzzle but my answer) ... and then of course the circle thing remains ... I *think* they are in a circle ... but that doesn't help me much, I think I should go to sleep and try again tomorrow, but I soo hate problems I can't figure out ... groans in frustration ...
the phrase
"The green bungalow is next to the left of the white bungalow" is where I'm having a bit of trouble ... is it the first house on the left, or the house one step beyond that (on the left side)?
The vagueness in what you say *seems* to point to a desired vagueness in response ... now I have read a bit of alchemy, but never noticed the fish without bones thing, sorry only had the least bit of jung and have no clue about aion. So hey, how about the AMERICAN, who has fish and cat's, smokes pall mall, yet prefers dunhill ... my pad is white, but I would like blue ... and I drink both beer and coffee, or then I can bring up the pisces aquarian cusp thing (birds and fish) ... but to be needlessly cryptic is just that ... it all comes down to understanding what is said ... without understanding that phrase I quoted above from the puzzle I cannot figure it out ... even if I solved it it would be for the wrong reasons ... I know english is not your native tongue, so the problem in and of itself is unclear but I wonder if you intended it to be as unclear as I am making it ...
I suspect that your more recent logic puzzle was like the last one and I thank you for making it less math entisive, but I cannot solve it without making assumptions and so by my standards it is flawed (not the puzzle but my answer) ... and then of course the circle thing remains ... I *think* they are in a circle ... but that doesn't help me much, I think I should go to sleep and try again tomorrow, but I soo hate problems I can't figure out ... groans in frustration ...
T
The Gardener
Guest
The fish belongs to the Norveigan.
T
The Gardener
Guest
"The person who smokes Pall Mall rears birds". This is sheer cointelpro. No one smokes Pall Mall. The person who rears birds smokes Prince, and is also known as Mr Green or Pole, who loves coffe.
The typo up there should say Norvegian, and not Norveigan, of course.
The typo up there should say Norvegian, and not Norveigan, of course.
Arrgg... I did this exact puzzle once before and arrived at a complete solution, however it was simply through working through the permutations one by one (a clumsy and "stupid" way of getting the answer to puzzles IMO). This time however, I did notice something else... the fact that we are never told that a fish is actually the "5th animal". The 5th animal might be an anteater or wallaby - so there we have an extra branch of possibilities. ;)
John Chang
Jedi
Oh, this one is tricky. I'm going to save myself some schlepping and use Maxima to manipulate these equations. And I don't have any paper or pencils at home, so it's pretty much the only way I have of doing this.
(%i1) e1: a + b = 10;
(%o1) b + a = 10
(%i2) e2: c+d = 16;
(%o2) d + c = 16
(%i3) e3: e+f = 26;
(%o3) f + e = 26
(%i5) e4: a*p1 + b*p2 = 35;
(%o5) b p2 + a p1 = 35
(%i6) e5: c*p1 + d*p2 = 35;
(%o6) d p2 + c p1 = 35
(%i7) e6: e*p1 + f*p2 = 35;
(%o7) f p2 + e p1 = 35
(%i10) solve ( [e1,e2,e3,e4,e5,e6], [a,b,c,d,e,f,p1,p2] );
10 %r5 - 35 10 %r4 - 35 16 %r5 - 35
(%o10) [[a = -----------, b = - -----------, c = -----------,
%r5 - %r4 %r5 - %r4 %r5 - %r4
16 %r4 - 35 26 %r5 - 35 26 %r4 - 35
d = - -----------, e = -----------, f = - -----------, p1 = %r4, p2 = %r5],
%r5 - %r4 %r5 - %r4 %r5 - %r4
35 10 %r6 - 35 35 16 %r6 - 35 35 26 %r6 - 35
[a = ---, b = -----------, c = ---, d = -----------, e = ---, f = -----------,
%r6 %r6 %r6 %r6 %r6 %r6
p1 = %r6, p2 = 0]]
Ok, now we have to read the output. The bottom solution is the degenerate one, if the second price is allowed to be zero. I assume that isn't the solution we're looking for, it's the upper one, the ambiguous one. That's what those %r5 and %r4 are telling us - the thing needs more input.
Well, since a,b,c,d,e,f can only be whole numbers, and positive greater than zero, we can fix the value of two of those, and get solutions. Studying those terms real closely, it looks like c and e are the real keys here. The denominator is always negative, which requires a tight range for p2. So, we have 16*26 combinations of c and e, and the rest is brute force key search.
Here's a solution:
(%i70) e7: c = 6; e8: e = 1; solve ( [e1,e2,e3,e4,e5,e6,e7,e8], [a,b,c,d,e,f,p1,p2] );
(%o70) c = 6
(%i71)
(%o71) e = 1
(%i72)
15 5
(%o72) [[a = 9, b = 1, c = 6, d = 10, e = 1, f = 25, p1 = --, p2 = -]]
4 4
It fits all the requirements - a thru f are nonzero and whole, and p2 is less than p1. There may be other solutions, but it's getting late, and I'm sleepy.
(%i1) e1: a + b = 10;
(%o1) b + a = 10
(%i2) e2: c+d = 16;
(%o2) d + c = 16
(%i3) e3: e+f = 26;
(%o3) f + e = 26
(%i5) e4: a*p1 + b*p2 = 35;
(%o5) b p2 + a p1 = 35
(%i6) e5: c*p1 + d*p2 = 35;
(%o6) d p2 + c p1 = 35
(%i7) e6: e*p1 + f*p2 = 35;
(%o7) f p2 + e p1 = 35
(%i10) solve ( [e1,e2,e3,e4,e5,e6], [a,b,c,d,e,f,p1,p2] );
10 %r5 - 35 10 %r4 - 35 16 %r5 - 35
(%o10) [[a = -----------, b = - -----------, c = -----------,
%r5 - %r4 %r5 - %r4 %r5 - %r4
16 %r4 - 35 26 %r5 - 35 26 %r4 - 35
d = - -----------, e = -----------, f = - -----------, p1 = %r4, p2 = %r5],
%r5 - %r4 %r5 - %r4 %r5 - %r4
35 10 %r6 - 35 35 16 %r6 - 35 35 26 %r6 - 35
[a = ---, b = -----------, c = ---, d = -----------, e = ---, f = -----------,
%r6 %r6 %r6 %r6 %r6 %r6
p1 = %r6, p2 = 0]]
Ok, now we have to read the output. The bottom solution is the degenerate one, if the second price is allowed to be zero. I assume that isn't the solution we're looking for, it's the upper one, the ambiguous one. That's what those %r5 and %r4 are telling us - the thing needs more input.
Well, since a,b,c,d,e,f can only be whole numbers, and positive greater than zero, we can fix the value of two of those, and get solutions. Studying those terms real closely, it looks like c and e are the real keys here. The denominator is always negative, which requires a tight range for p2. So, we have 16*26 combinations of c and e, and the rest is brute force key search.
Here's a solution:
(%i70) e7: c = 6; e8: e = 1; solve ( [e1,e2,e3,e4,e5,e6,e7,e8], [a,b,c,d,e,f,p1,p2] );
(%o70) c = 6
(%i71)
(%o71) e = 1
(%i72)
15 5
(%o72) [[a = 9, b = 1, c = 6, d = 10, e = 1, f = 25, p1 = --, p2 = -]]
4 4
It fits all the requirements - a thru f are nonzero and whole, and p2 is less than p1. There may be other solutions, but it's getting late, and I'm sleepy.
highmystica
Jedi Master
oh sadness - I came back to re-read the question now that I've slept and it seems to have been solved ...
Hey ark, I was wondering if perhaps you could start a new thing here with similar questions yet keep the questions and answers on different threads ...
Hey ark, I was wondering if perhaps you could start a new thing here with similar questions yet keep the questions and answers on different threads ...
