Galaxia2002
Dagobah Resident
Z said:osher said:If my Lugol's is 10mg I + 20mg KI in 1g of liquid, how much percentage is it? 30%?
The most important thing is the level of Iodine per 1 drop.
One metric drop should be 0.5 ml ( but this is subjective so instead of pipette I suggest using 1 ml syringe) this equals 0.5 grams.
So it follows that one drop of your solution contains 5mg of Iodine and 10 mg of KI.
Now since KI is not just Iodine we need to establish the quantity of Iodine.
Potassium molecular weight is 39
Iodine molecular weight is 127
Potassium iodide is therefore 166
So percent iodine in KI is 127/166*100= 76.5 %
So of the 10mg you need to count 76.5/100*10 = 7.65 mg
Therefore one drop of your solution has total of 7.65 + 5 =12.65g of Iodine.
Which happens to be maintenance dose per day for people who have no serious health issues.
The calculation is not right.
76.5 % of the 20 mg are iodine. So this is 20*76.5/100 = 15.3 mg of iodine
You have to take into account the whole 10 mg of iodine because it is already in its elemental form so you have 15.3 mg + 10 mg = 25.3 mg of total iodine per 1 g of solution .
in 1 g of solution (about 1 ml) there is about 20 drops (you can adjust this value with the same dropper you will use to take it) 25.3 mg/20 drop by ml = 1.26 mg per drop. So that lugol's is really low in iodine.